A child is holding a 5.00 L helium-filled balloon. The temperature of the balloon is 294 K and the pressure inside the balloon is 0.966 atm. If the child accidentally lets go of the balloon and it floats up to a place high in the sky where the temperature is only 261 K and the pressure drops to 0.78 atm, what will be the new volume of the balloon?
We can organize the information from the problem in a table:
- initialfinalP0.966 atm0.78 atmV5.00 L?T294 K261 K
It is worth noting that temperatures are rarely recorded in Kelvin, but we'll deal with that later.
In this case, amount is never mentioned, so we'll eliminate that from the formula.
Then we'll solve it for Vf
Substituting in our values allows us to solve the problem:
Here's another example with much more annoying units.
A 5.40 L balloon holds 10.0 g of carbon dioxide at 34oC and 1.06 atm. If 0.227 moles of carbon dioxide are added to the balloon, the pressure changes to 1500 mm Hg and the temperature drops to -17.2oC, what will the new volume be?
- initialfinalP1.06 atm1500 mm HgV5.40 L?T34oC-17.2oCn10.0 g CO2+ 0.227 mols
First, temperature MUST be in Kelvin, so we'll need to change both temperatures by adding 273.15 to each value.
- initialfinalP1.06 atm1500 mm HgV5.40 L?T307 K256.0 Kn10.0 g CO2+ 0.227 mols
We also need to figure out the values for amount. First we'll convert the mass of CO2 to moles
then we'll add the 0.227 moles. This will leave us with this data table:
- initialfinalP1.06 atm1.97 atmV5.40 L?T307 K256.0 Kn0.227 mol0.454 mol
There is nothing to eliminate here (all variables are being used), so we can rearrange this to solve for Vf:
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