Converting Between Moles and the Volume of a Solution

To convert between moles and the volume of a solution we will be using the factor label method from the first unit.

For these problems, we will be using molarity as the conversion factor.

You will, of course, need to remember that molarity is the number of moles found in 1 liter of solution. In other words, a 3.11 M solution of table salt contains 3.11 moles of NaCl for every liter of solution.

Let's try some problems 

How many liters of a 2.56 M solution of NaCl contain 8.93 moles of sodium chloride? (What is important in this (and in all molarity problems) is that you do NOT start with molarity. Molarity is a ratio, it is NOT an amount and therefore should never be used as the given in a problem.)

How many moles of copper II nitrate can be found in 38.1 liters of a 2.61 M solution? 

And, one other problem: How many moles of copper II nitrate can be found in 38.1 mL of a 2.61 L solution? 
Note that this problem is the same as the last one EXCEPT that you are given mL instead of L.