Calculating Molecular formulas continued

Now that you’ve done one example, let’s try another:

A compound has an empirical formula of C₃H₆O₂. If the molar mass is approximately 296 g/mol what is the molecular formula?

Here’s the table set up initially:

The empirical mass is is 74, which is 1/4th of 296

Multiplying the empirical formula by the same factor gives C₁₂H₂₄O₈